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1312155423323 is a prime number
BaseRepresentation
bin10011000110000010100…
…011101101001001011011
311122102220100220221021222
4103012002203231021123
5132444243242021243
62442443524322255
7163541302033343
oct23060243551133
94572810827258
101312155423323
1146653358a698
1219237a24338b
1396974509514
1447719aa3d23
15241eb147168
hex131828ed25b

1312155423323 has 2 divisors, whose sum is σ = 1312155423324. Its totient is φ = 1312155423322.

The previous prime is 1312155423289. The next prime is 1312155423343. The reversal of 1312155423323 is 3233245512131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3233245512131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312155423323 - 28 = 1312155423067 is a prime.

It is a super-2 number, since 2×13121554233232 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1312155423343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656077711661 + 656077711662.

It is an arithmetic number, because the mean of its divisors is an integer number (656077711662).

Almost surely, 21312155423323 is an apocalyptic number.

1312155423323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312155423323 is an equidigital number, since it uses as much as digits as its factorization.

1312155423323 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 64800, while the sum is 35.

The spelling of 1312155423323 in words is "one trillion, three hundred twelve billion, one hundred fifty-five million, four hundred twenty-three thousand, three hundred twenty-three".