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32334014113 is a prime number
BaseRepresentation
bin11110000111010000…
…011110011010100001
310002110102011002211021
4132013100132122201
51012210001422423
622504250045441
72223160404502
oct360720363241
9102412132737
1032334014113
1112792787415
126324719881
133083ab933b
1417ca40cba9
15c939b895d
hex78741e6a1

32334014113 has 2 divisors, whose sum is σ = 32334014114. Its totient is φ = 32334014112.

The previous prime is 32334014107. The next prime is 32334014129. The reversal of 32334014113 is 31141043323.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26210638609 + 6123375504 = 161897^2 + 78252^2 .

It is a cyclic number.

It is not a de Polignac number, because 32334014113 - 217 = 32333883041 is a prime.

It is not a weakly prime, because it can be changed into another prime (32334014183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16167007056 + 16167007057.

It is an arithmetic number, because the mean of its divisors is an integer number (16167007057).

Almost surely, 232334014113 is an apocalyptic number.

It is an amenable number.

32334014113 is a deficient number, since it is larger than the sum of its proper divisors (1).

32334014113 is an equidigital number, since it uses as much as digits as its factorization.

32334014113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 32334014113 its reverse (31141043323), we get a palindrome (63475057436).

The spelling of 32334014113 in words is "thirty-two billion, three hundred thirty-four million, fourteen thousand, one hundred thirteen".