Base | Representation |
---|---|
bin | 1001011010011000111… |
… | …00011010101101011011 |
3 | 1010220202122200112010021 |
4 | 10231030130122231123 |
5 | 20244313144040201 |
6 | 404323100531311 |
7 | 32236164460525 |
oct | 4551434325533 |
9 | 1126678615107 |
10 | 323405065051 |
11 | 115178801072 |
12 | 52817850b37 |
13 | 2465cab3923 |
14 | 1191d752a15 |
15 | 862c332ea1 |
hex | 4b4c71ab5b |
323405065051 has 2 divisors, whose sum is σ = 323405065052. Its totient is φ = 323405065050.
The previous prime is 323405065037. The next prime is 323405065063. The reversal of 323405065051 is 150560504323.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-323405065051 is a prime.
It is a super-2 number, since 2×3234050650512 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 323405064998 and 323405065016.
It is not a weakly prime, because it can be changed into another prime (323405065031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161702532525 + 161702532526.
It is an arithmetic number, because the mean of its divisors is an integer number (161702532526).
Almost surely, 2323405065051 is an apocalyptic number.
323405065051 is a deficient number, since it is larger than the sum of its proper divisors (1).
323405065051 is an equidigital number, since it uses as much as digits as its factorization.
323405065051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 323405065051 its reverse (150560504323), we get a palindrome (473965569374).
The spelling of 323405065051 in words is "three hundred twenty-three billion, four hundred five million, sixty-five thousand, fifty-one".
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