Base | Representation |
---|---|
bin | 101111000011111111111… |
… | …110101000001010100101 |
3 | 102110011210200120012202201 |
4 | 233003333332220022211 |
5 | 410441424130422432 |
6 | 10513421333334501 |
7 | 452441155354303 |
oct | 57037776501245 |
9 | 12404720505681 |
10 | 3234110014117 |
11 | 103763a876394 |
12 | 442960a97431 |
13 | 1a5c8a874488 |
14 | b2763213273 |
15 | 591d7548ee7 |
hex | 2f0fffa82a5 |
3234110014117 has 2 divisors, whose sum is σ = 3234110014118. Its totient is φ = 3234110014116.
The previous prime is 3234110014067. The next prime is 3234110014147. The reversal of 3234110014117 is 7114100114323.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2968432651396 + 265677362721 = 1722914^2 + 515439^2 .
It is a cyclic number.
It is not a de Polignac number, because 3234110014117 - 223 = 3234101625509 is a prime.
It is a super-3 number, since 3×32341100141173 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3234110014147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1617055007058 + 1617055007059.
It is an arithmetic number, because the mean of its divisors is an integer number (1617055007059).
Almost surely, 23234110014117 is an apocalyptic number.
It is an amenable number.
3234110014117 is a deficient number, since it is larger than the sum of its proper divisors (1).
3234110014117 is an equidigital number, since it uses as much as digits as its factorization.
3234110014117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
The spelling of 3234110014117 in words is "three trillion, two hundred thirty-four billion, one hundred ten million, fourteen thousand, one hundred seventeen".
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