Base | Representation |
---|---|
bin | 101111000100000101100… |
… | …110010110010110101001 |
3 | 102110012001021000002111222 |
4 | 233010011212112112221 |
5 | 410442122301004001 |
6 | 10513434542431425 |
7 | 452443412033204 |
oct | 57040546262651 |
9 | 12405037002458 |
10 | 3234204313001 |
11 | 1037689023552 |
12 | 442988592575 |
13 | 1a5ca427002c |
14 | b277195c93b |
15 | 591e097461b |
hex | 2f1059965a9 |
3234204313001 has 2 divisors, whose sum is σ = 3234204313002. Its totient is φ = 3234204313000.
The previous prime is 3234204312961. The next prime is 3234204313003. The reversal of 3234204313001 is 1003134024323.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2005041840025 + 1229162472976 = 1415995^2 + 1108676^2 .
It is a cyclic number.
It is not a de Polignac number, because 3234204313001 - 210 = 3234204311977 is a prime.
Together with 3234204313003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3234204313003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1617102156500 + 1617102156501.
It is an arithmetic number, because the mean of its divisors is an integer number (1617102156501).
Almost surely, 23234204313001 is an apocalyptic number.
It is an amenable number.
3234204313001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3234204313001 is an equidigital number, since it uses as much as digits as its factorization.
3234204313001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 3234204313001 its reverse (1003134024323), we get a palindrome (4237338337324).
The spelling of 3234204313001 in words is "three trillion, two hundred thirty-four billion, two hundred four million, three hundred thirteen thousand, one".
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