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323538403973171 is a prime number
BaseRepresentation
bin100100110010000011010011…
…1101000111101100000110011
31120102112222011122202001111012
41021210012213220331200303
5314401323122404120141
63104035254011341135
7125101610155155002
oct11144064750754063
91512488148661435
10323538403973171
11940a8959461132
1230353ab0a517ab
1310b6b70487459a
1459c74b13dcc39
152760e9a38bceb
hex12641a7a3d833

323538403973171 has 2 divisors, whose sum is σ = 323538403973172. Its totient is φ = 323538403973170.

The previous prime is 323538403973027. The next prime is 323538403973173. The reversal of 323538403973171 is 171379304835323.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 323538403973171 - 230 = 323537330231347 is a prime.

Together with 323538403973173, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 323538403973171.

It is not a weakly prime, because it can be changed into another prime (323538403973173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161769201986585 + 161769201986586.

It is an arithmetic number, because the mean of its divisors is an integer number (161769201986586).

Almost surely, 2323538403973171 is an apocalyptic number.

323538403973171 is a deficient number, since it is larger than the sum of its proper divisors (1).

323538403973171 is an equidigital number, since it uses as much as digits as its factorization.

323538403973171 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34292160, while the sum is 59.

The spelling of 323538403973171 in words is "three hundred twenty-three trillion, five hundred thirty-eight billion, four hundred three million, nine hundred seventy-three thousand, one hundred seventy-one".