Base | Representation |
---|---|
bin | 1100000100011110… |
… | …1010111010100101 |
3 | 22100210122201221011 |
4 | 3001013222322211 |
5 | 23113420412402 |
6 | 1253300422221 |
7 | 143201442301 |
oct | 30107527245 |
9 | 8323581834 |
10 | 3240013477 |
11 | 14129a3098 |
12 | 7650a7971 |
13 | 3c833b54c |
14 | 22a442d01 |
15 | 13e6a3ed7 |
hex | c11eaea5 |
3240013477 has 2 divisors, whose sum is σ = 3240013478. Its totient is φ = 3240013476.
The previous prime is 3240013463. The next prime is 3240013499. The reversal of 3240013477 is 7743100423.
3240013477 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2967961441 + 272052036 = 54479^2 + 16494^2 .
It is a cyclic number.
It is not a de Polignac number, because 3240013477 - 27 = 3240013349 is a prime.
It is a super-2 number, since 2×32400134772 = 20995374662283259058, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3240013177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1620006738 + 1620006739.
It is an arithmetic number, because the mean of its divisors is an integer number (1620006739).
Almost surely, 23240013477 is an apocalyptic number.
It is an amenable number.
3240013477 is a deficient number, since it is larger than the sum of its proper divisors (1).
3240013477 is an equidigital number, since it uses as much as digits as its factorization.
3240013477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14112, while the sum is 31.
The square root of 3240013477 is about 56921.1162662856. The cubic root of 3240013477 is about 1479.7292962708.
The spelling of 3240013477 in words is "three billion, two hundred forty million, thirteen thousand, four hundred seventy-seven".
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