Base | Representation |
---|---|
bin | 101111001001110000111… |
… | …101011101100011111001 |
3 | 102110202210010001112122121 |
4 | 233021300331131203321 |
5 | 411042113412014431 |
6 | 10520323513121241 |
7 | 453050444546566 |
oct | 57116075354371 |
9 | 12422703045577 |
10 | 3240300501241 |
11 | 103a227181a51 |
12 | 443baa0b9221 |
13 | 1a67362465cb |
14 | b2b8d44986d |
15 | 5944ac5c611 |
hex | 2f270f5d8f9 |
3240300501241 has 2 divisors, whose sum is σ = 3240300501242. Its totient is φ = 3240300501240.
The previous prime is 3240300501173. The next prime is 3240300501257. The reversal of 3240300501241 is 1421050030423.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2087941190841 + 1152359310400 = 1444971^2 + 1073480^2 .
It is a cyclic number.
It is not a de Polignac number, because 3240300501241 - 213 = 3240300493049 is a prime.
It is not a weakly prime, because it can be changed into another prime (3240300501941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1620150250620 + 1620150250621.
It is an arithmetic number, because the mean of its divisors is an integer number (1620150250621).
Almost surely, 23240300501241 is an apocalyptic number.
It is an amenable number.
3240300501241 is a deficient number, since it is larger than the sum of its proper divisors (1).
3240300501241 is an equidigital number, since it uses as much as digits as its factorization.
3240300501241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 3240300501241 its reverse (1421050030423), we get a palindrome (4661350531664).
The spelling of 3240300501241 in words is "three trillion, two hundred forty billion, three hundred million, five hundred one thousand, two hundred forty-one".
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