Base | Representation |
---|---|
bin | 101111001001111111011… |
… | …000010110111101100001 |
3 | 102110210101222021221210121 |
4 | 233021333120112331201 |
5 | 411043112330324441 |
6 | 10520403514400241 |
7 | 453056443126420 |
oct | 57117730267541 |
9 | 12423358257717 |
10 | 3240542433121 |
11 | 103a3407a4a54 |
12 | 444057130081 |
13 | 1a67743c2876 |
14 | b2bb36252b7 |
15 | 594620eadd1 |
hex | 2f27f616f61 |
3240542433121 has 16 divisors (see below), whose sum is σ = 3846380820480. Its totient is φ = 2672433308880.
The previous prime is 3240542433113. The next prime is 3240542433131. The reversal of 3240542433121 is 1213342450423.
It is a cyclic number.
It is not a de Polignac number, because 3240542433121 - 23 = 3240542433113 is a prime.
It is a super-2 number, since 2×32405424331212 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3240542433101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83452395 + ... + 83491216.
It is an arithmetic number, because the mean of its divisors is an integer number (240398801280).
Almost surely, 23240542433121 is an apocalyptic number.
It is an amenable number.
3240542433121 is a deficient number, since it is larger than the sum of its proper divisors (605838387359).
3240542433121 is a wasteful number, since it uses less digits than its factorization.
3240542433121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 166943724.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 3240542433121 its reverse (1213342450423), we get a palindrome (4453884883544).
The spelling of 3240542433121 in words is "three trillion, two hundred forty billion, five hundred forty-two million, four hundred thirty-three thousand, one hundred twenty-one".
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