Base | Representation |
---|---|
bin | 1001011011101101001… |
… | …01010101001111101011 |
3 | 1010222120220222211100010 |
4 | 10231312211111033223 |
5 | 20302240140420120 |
6 | 404521153543003 |
7 | 32262540632622 |
oct | 4556645251753 |
9 | 1128526884303 |
10 | 324112045035 |
11 | 115500888649 |
12 | 52994574a63 |
13 | 247433c808c |
14 | 119895c66b9 |
15 | 866e4337e0 |
hex | 4b769553eb |
324112045035 has 32 divisors (see below), whose sum is σ = 559785738240. Its totient is φ = 159642589568.
The previous prime is 324112045007. The next prime is 324112045039. The reversal of 324112045035 is 530540211423.
It is a cyclic number.
It is not a de Polignac number, because 324112045035 - 28 = 324112044779 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 324112044993 and 324112045011.
It is not an unprimeable number, because it can be changed into a prime (324112045039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16187499 + ... + 16207508.
It is an arithmetic number, because the mean of its divisors is an integer number (17493304320).
Almost surely, 2324112045035 is an apocalyptic number.
324112045035 is a deficient number, since it is larger than the sum of its proper divisors (235673693205).
324112045035 is a wasteful number, since it uses less digits than its factorization.
324112045035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32395067.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 324112045035 its reverse (530540211423), we get a palindrome (854652256458).
The spelling of 324112045035 in words is "three hundred twenty-four billion, one hundred twelve million, forty-five thousand, thirty-five".
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