Base | Representation |
---|---|
bin | 101111001011100011111… |
… | …111001001010011101101 |
3 | 102110221202121100121121211 |
4 | 233023203333021103231 |
5 | 411110041430304123 |
6 | 10521243211554421 |
7 | 453146330011435 |
oct | 57134377112355 |
9 | 12427677317554 |
10 | 3242230322413 |
11 | 1040027546185 |
12 | 44444845ba11 |
13 | 1a6982cbb924 |
14 | b2cd38772c5 |
15 | 595103ab40d |
hex | 2f2e3fc94ed |
3242230322413 has 2 divisors, whose sum is σ = 3242230322414. Its totient is φ = 3242230322412.
The previous prime is 3242230322389. The next prime is 3242230322423. The reversal of 3242230322413 is 3142230322423.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2923816146889 + 318414175524 = 1709917^2 + 564282^2 .
It is a cyclic number.
It is not a de Polignac number, because 3242230322413 - 229 = 3241693451501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3242230322423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1621115161206 + 1621115161207.
It is an arithmetic number, because the mean of its divisors is an integer number (1621115161207).
Almost surely, 23242230322413 is an apocalyptic number.
It is an amenable number.
3242230322413 is a deficient number, since it is larger than the sum of its proper divisors (1).
3242230322413 is an equidigital number, since it uses as much as digits as its factorization.
3242230322413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 3242230322413 its reverse (3142230322423), we get a palindrome (6384460644836).
The spelling of 3242230322413 in words is "three trillion, two hundred forty-two billion, two hundred thirty million, three hundred twenty-two thousand, four hundred thirteen".
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