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3242552000053 is a prime number
BaseRepresentation
bin101111001011110111001…
…010001111111000110101
3102110222121000122112101111
4233023313022033320311
5411111221303000203
610521335142355021
7453160314145222
oct57136712177065
912428530575344
103242552000053
111040182086373
1244451812ba71
131a6a04839622
14b2d24490949
155952d74d26d
hex2f2f728fe35

3242552000053 has 2 divisors, whose sum is σ = 3242552000054. Its totient is φ = 3242552000052.

The previous prime is 3242552000047. The next prime is 3242552000113. The reversal of 3242552000053 is 3500002552423.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3186374941764 + 56177058289 = 1785042^2 + 237017^2 .

It is a cyclic number.

It is not a de Polignac number, because 3242552000053 - 29 = 3242551999541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3242551999979 and 3242552000024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3242552006053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1621276000026 + 1621276000027.

It is an arithmetic number, because the mean of its divisors is an integer number (1621276000027).

Almost surely, 23242552000053 is an apocalyptic number.

It is an amenable number.

3242552000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

3242552000053 is an equidigital number, since it uses as much as digits as its factorization.

3242552000053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36000, while the sum is 31.

Adding to 3242552000053 its reverse (3500002552423), we get a palindrome (6742554552476).

The spelling of 3242552000053 in words is "three trillion, two hundred forty-two billion, five hundred fifty-two million, fifty-three", and thus it is an aban number.