Base | Representation |
---|---|
bin | 101111001100100000111… |
… | …010001100010011001101 |
3 | 102111001101211122021022011 |
4 | 233030200322030103031 |
5 | 411114140110343000 |
6 | 10521532443221221 |
7 | 453213550555114 |
oct | 57144072142315 |
9 | 12431354567264 |
10 | 3243252434125 |
11 | 10405014a1900 |
12 | 444692817811 |
13 | 1a6ab699b462 |
14 | b2d8d4dcc7b |
15 | 5956eea92ba |
hex | 2f320e8c4cd |
3243252434125 has 48 divisors (see below), whose sum is σ = 4451053501440. Its totient is φ = 2357636028000.
The previous prime is 3243252434113. The next prime is 3243252434197. The reversal of 3243252434125 is 5214342523423.
It is not a de Polignac number, because 3243252434125 - 221 = 3243250336973 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 33332296 + ... + 33429454.
It is an arithmetic number, because the mean of its divisors is an integer number (92730281280).
Almost surely, 23243252434125 is an apocalyptic number.
It is an amenable number.
3243252434125 is a deficient number, since it is larger than the sum of its proper divisors (1207801067315).
3243252434125 is a wasteful number, since it uses less digits than its factorization.
3243252434125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99403 (or 99382 counting only the distinct ones).
The product of its digits is 691200, while the sum is 40.
Adding to 3243252434125 its reverse (5214342523423), we get a palindrome (8457594957548).
The spelling of 3243252434125 in words is "three trillion, two hundred forty-three billion, two hundred fifty-two million, four hundred thirty-four thousand, one hundred twenty-five".
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