Base | Representation |
---|---|
bin | 101111001110001100101… |
… | …011110100010111101111 |
3 | 102111020001212000220000111 |
4 | 233032030223310113233 |
5 | 411131341003333143 |
6 | 10522432114440451 |
7 | 453306425014420 |
oct | 57161453642757 |
9 | 12436055026014 |
10 | 3245060605423 |
11 | 104124a12774a |
12 | 444ab8293127 |
13 | 1a701448c8c0 |
14 | b30c1701647 |
15 | 59628ac899d |
hex | 2f38caf45ef |
3245060605423 has 32 divisors (see below), whose sum is σ = 4059757520000. Its totient is φ = 2525204367360.
The previous prime is 3245060605411. The next prime is 3245060605427.
3245060605423 is nontrivially palindromic in base 10.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3245060605423 is a prime.
It is a super-3 number, since 3×32450606054233 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3245060605427) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 90180211 + ... + 90216187.
It is an arithmetic number, because the mean of its divisors is an integer number (126867422500).
Almost surely, 23245060605423 is an apocalyptic number.
3245060605423 is a deficient number, since it is larger than the sum of its proper divisors (814696914577).
3245060605423 is a wasteful number, since it uses less digits than its factorization.
3245060605423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52307.
The product of its (nonzero) digits is 518400, while the sum is 40.
The spelling of 3245060605423 in words is "three trillion, two hundred forty-five billion, sixty million, six hundred five thousand, four hundred twenty-three".
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