Base | Representation |
---|---|
bin | 101111010010110100111… |
… | …100111010000010111011 |
3 | 102111200220020222021001122 |
4 | 233102310330322002323 |
5 | 411222030433003201 |
6 | 10525013234335455 |
7 | 453543541614062 |
oct | 57226474720273 |
9 | 12450806867048 |
10 | 3250031141051 |
11 | 104336a93a732 |
12 | 445a64a2a58b |
13 | 1a76271a3246 |
14 | b34338d31d9 |
15 | 5981a15ee1b |
hex | 2f4b4f3a0bb |
3250031141051 has 2 divisors, whose sum is σ = 3250031141052. Its totient is φ = 3250031141050.
The previous prime is 3250031141047. The next prime is 3250031141053. The reversal of 3250031141051 is 1501411300523.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3250031141051 - 22 = 3250031141047 is a prime.
Together with 3250031141053, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3250031141051.
It is not a weakly prime, because it can be changed into another prime (3250031141053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1625015570525 + 1625015570526.
It is an arithmetic number, because the mean of its divisors is an integer number (1625015570526).
Almost surely, 23250031141051 is an apocalyptic number.
3250031141051 is a deficient number, since it is larger than the sum of its proper divisors (1).
3250031141051 is an equidigital number, since it uses as much as digits as its factorization.
3250031141051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 3250031141051 its reverse (1501411300523), we get a palindrome (4751442441574).
The spelling of 3250031141051 in words is "three trillion, two hundred fifty billion, thirty-one million, one hundred forty-one thousand, fifty-one".
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