Base | Representation |
---|---|
bin | 101111010010110101100… |
… | …000110001111101100001 |
3 | 102111200220220200001000112 |
4 | 233102311200301331201 |
5 | 411222040334420441 |
6 | 10525014212101105 |
7 | 453544014552146 |
oct | 57226540617541 |
9 | 12450826601015 |
10 | 3250040545121 |
11 | 1043375183097 |
12 | 445a68004795 |
13 | 1a7629116796 |
14 | b3434c603cd |
15 | 5981adbb4eb |
hex | 2f4b5831f61 |
3250040545121 has 2 divisors, whose sum is σ = 3250040545122. Its totient is φ = 3250040545120.
The previous prime is 3250040545117. The next prime is 3250040545163. The reversal of 3250040545121 is 1215450400523.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2589006503521 + 661034041600 = 1609039^2 + 813040^2 .
It is a cyclic number.
It is not a de Polignac number, because 3250040545121 - 22 = 3250040545117 is a prime.
It is not a weakly prime, because it can be changed into another prime (3250040545021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1625020272560 + 1625020272561.
It is an arithmetic number, because the mean of its divisors is an integer number (1625020272561).
Almost surely, 23250040545121 is an apocalyptic number.
It is an amenable number.
3250040545121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3250040545121 is an equidigital number, since it uses as much as digits as its factorization.
3250040545121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 3250040545121 its reverse (1215450400523), we get a palindrome (4465490945644).
The spelling of 3250040545121 in words is "three trillion, two hundred fifty billion, forty million, five hundred forty-five thousand, one hundred twenty-one".
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