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3250040545121 is a prime number
BaseRepresentation
bin101111010010110101100…
…000110001111101100001
3102111200220220200001000112
4233102311200301331201
5411222040334420441
610525014212101105
7453544014552146
oct57226540617541
912450826601015
103250040545121
111043375183097
12445a68004795
131a7629116796
14b3434c603cd
155981adbb4eb
hex2f4b5831f61

3250040545121 has 2 divisors, whose sum is σ = 3250040545122. Its totient is φ = 3250040545120.

The previous prime is 3250040545117. The next prime is 3250040545163. The reversal of 3250040545121 is 1215450400523.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2589006503521 + 661034041600 = 1609039^2 + 813040^2 .

It is a cyclic number.

It is not a de Polignac number, because 3250040545121 - 22 = 3250040545117 is a prime.

It is not a weakly prime, because it can be changed into another prime (3250040545021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1625020272560 + 1625020272561.

It is an arithmetic number, because the mean of its divisors is an integer number (1625020272561).

Almost surely, 23250040545121 is an apocalyptic number.

It is an amenable number.

3250040545121 is a deficient number, since it is larger than the sum of its proper divisors (1).

3250040545121 is an equidigital number, since it uses as much as digits as its factorization.

3250040545121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24000, while the sum is 32.

Adding to 3250040545121 its reverse (1215450400523), we get a palindrome (4465490945644).

The spelling of 3250040545121 in words is "three trillion, two hundred fifty billion, forty million, five hundred forty-five thousand, one hundred twenty-one".