325011490429 has 2 divisors, whose sum is σ = 325011490430. Its totient is φ = 325011490428.

The previous prime is 325011490357. The next prime is 325011490451. The reversal of 325011490429 is 924094110523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 323531164804 + 1480325625 = 568798^2 + 38475^2 .

It is a cyclic number.

It is not a de Polignac number, because 325011490429 - 2¹⁷ = 325011359357 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 325011490391 and 325011490400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (325011470429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162505745214 + 162505745215.

It is an arithmetic number, because the mean of its divisors is an integer number (162505745215).

Almost surely, 2^325011490429 is an apocalyptic number.

It is an amenable number.

325011490429 is a deficient number, since it is larger than the sum of its proper divisors (1).

325011490429 is an equidigital number, since it uses as much as digits as its factorization.

325011490429 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 40.

The spelling of 325011490429 in words is "three hundred twenty-five billion, eleven million, four hundred ninety thousand, four hundred twenty-nine".