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3250226597 is a prime number
BaseRepresentation
bin1100000110111010…
…1000010110100101
322101111212121200212
43001232220112211
523124024222342
61254303345205
7143354320202
oct30156502645
98344777625
103250226597
111418739392
127685b2205
133ca4a6107
1422b940ca9
15140520182
hexc1ba85a5

3250226597 has 2 divisors, whose sum is σ = 3250226598. Its totient is φ = 3250226596.

The previous prime is 3250226489. The next prime is 3250226641. The reversal of 3250226597 is 7956220523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3226353601 + 23872996 = 56801^2 + 4886^2 .

It is an emirp because it is prime and its reverse (7956220523) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3250226597 - 212 = 3250222501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3250286597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1625113298 + 1625113299.

It is an arithmetic number, because the mean of its divisors is an integer number (1625113299).

Almost surely, 23250226597 is an apocalyptic number.

It is an amenable number.

3250226597 is a deficient number, since it is larger than the sum of its proper divisors (1).

3250226597 is an equidigital number, since it uses as much as digits as its factorization.

3250226597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 41.

The square root of 3250226597 is about 57010.7586074769. The cubic root of 3250226597 is about 1481.2824586714.

The spelling of 3250226597 in words is "three billion, two hundred fifty million, two hundred twenty-six thousand, five hundred ninety-seven".