Base | Representation |
---|---|
bin | 100100111100111010000110… |
… | …1001011010111000011111101 |
3 | 1120121211121102200112112011112 |
4 | 1021321310031023113003331 |
5 | 320100244341023004440 |
6 | 3111140533230531405 |
7 | 125314450553634116 |
oct | 11171641513270375 |
9 | 1517747380475145 |
10 | 325030461141245 |
11 | 9462370a873312 |
12 | 305550b7966b65 |
13 | 10c49319542a32 |
14 | 5a397b5c0320d |
15 | 2789bc527e965 |
hex | 1279d0d2d70fd |
325030461141245 has 64 divisors (see below), whose sum is σ = 426397535424000. Its totient is φ = 236906644939776.
The previous prime is 325030461141229. The next prime is 325030461141263. The reversal of 325030461141245 is 542141164030523.
It is not a de Polignac number, because 325030461141245 - 24 = 325030461141229 is a prime.
It is a super-3 number, since 3×3250304611412453 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3436410224 + ... + 3436504806.
It is an arithmetic number, because the mean of its divisors is an integer number (6662461491000).
Almost surely, 2325030461141245 is an apocalyptic number.
It is an amenable number.
325030461141245 is a deficient number, since it is larger than the sum of its proper divisors (101367074282755).
325030461141245 is a wasteful number, since it uses less digits than its factorization.
325030461141245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 99542.
The product of its (nonzero) digits is 345600, while the sum is 41.
The spelling of 325030461141245 in words is "three hundred twenty-five trillion, thirty billion, four hundred sixty-one million, one hundred forty-one thousand, two hundred forty-five".
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