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32503345200041 is a prime number
BaseRepresentation
bin1110110001111110001100…
…10110000011101110101001
311021002021211000100002110112
413120333012112003232221
513230013322332400131
6153043455230424105
76563201123452502
oct730770626035651
9137067730302415
1032503345200041
11a3a1656006671
12378b448662035
13151a08ab9b0a1
14805255443ba9
153b574741a02b
hex1d8fc6583ba9

32503345200041 has 2 divisors, whose sum is σ = 32503345200042. Its totient is φ = 32503345200040.

The previous prime is 32503345200019. The next prime is 32503345200101. The reversal of 32503345200041 is 14000254330523.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25255248211600 + 7248096988441 = 5025460^2 + 2692229^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32503345200041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32503345199980 and 32503345200007.

It is not a weakly prime, because it can be changed into another prime (32503345205041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16251672600020 + 16251672600021.

It is an arithmetic number, because the mean of its divisors is an integer number (16251672600021).

Almost surely, 232503345200041 is an apocalyptic number.

It is an amenable number.

32503345200041 is a deficient number, since it is larger than the sum of its proper divisors (1).

32503345200041 is an equidigital number, since it uses as much as digits as its factorization.

32503345200041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 32.

Adding to 32503345200041 its reverse (14000254330523), we get a palindrome (46503599530564).

The spelling of 32503345200041 in words is "thirty-two trillion, five hundred three billion, three hundred forty-five million, two hundred thousand, forty-one".