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325067371957 is a prime number
BaseRepresentation
bin1001011101011111000…
…01100111010110110101
31011002001111121110111201
410232233201213112311
520311214221400312
6405200041532501
732325321033406
oct4565741472665
91132044543451
10325067371957
11115951069929
12530004a4131
13248662c3693
1411a3a4259ad
1586c823d557
hex4baf8675b5

325067371957 has 2 divisors, whose sum is σ = 325067371958. Its totient is φ = 325067371956.

The previous prime is 325067371943. The next prime is 325067371987. The reversal of 325067371957 is 759173760523.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 206996790961 + 118070580996 = 454969^2 + 343614^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-325067371957 is a prime.

It is a super-2 number, since 2×3250673719572 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 325067371898 and 325067371907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (325067371927) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162533685978 + 162533685979.

It is an arithmetic number, because the mean of its divisors is an integer number (162533685979).

Almost surely, 2325067371957 is an apocalyptic number.

It is an amenable number.

325067371957 is a deficient number, since it is larger than the sum of its proper divisors (1).

325067371957 is an equidigital number, since it uses as much as digits as its factorization.

325067371957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8334900, while the sum is 55.

The spelling of 325067371957 in words is "three hundred twenty-five billion, sixty-seven million, three hundred seventy-one thousand, nine hundred fifty-seven".