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32513303274341 is a prime number
BaseRepresentation
bin1110110010010000101111…
…11001000110001101100101
311021010020112000012200100012
413121020113321012031211
513230144221114234331
6153052223314500005
76564002651626211
oct731102771061545
9137106460180305
1032513303274341
11a3a58a609523a
123791367594605
13151acb6c99346
1480591bbb1941
153b5b2b79582b
hex1d9217e46365

32513303274341 has 2 divisors, whose sum is σ = 32513303274342. Its totient is φ = 32513303274340.

The previous prime is 32513303274269. The next prime is 32513303274401. The reversal of 32513303274341 is 14347230331523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31659989211841 + 853314062500 = 5626721^2 + 923750^2 .

It is a cyclic number.

It is not a de Polignac number, because 32513303274341 - 210 = 32513303273317 is a prime.

It is a super-2 number, since 2×325133032743412 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32513303271341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16256651637170 + 16256651637171.

It is an arithmetic number, because the mean of its divisors is an integer number (16256651637171).

Almost surely, 232513303274341 is an apocalyptic number.

It is an amenable number.

32513303274341 is a deficient number, since it is larger than the sum of its proper divisors (1).

32513303274341 is an equidigital number, since it uses as much as digits as its factorization.

32513303274341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 41.

The spelling of 32513303274341 in words is "thirty-two trillion, five hundred thirteen billion, three hundred three million, two hundred seventy-four thousand, three hundred forty-one".