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3252532106651 is a prime number
BaseRepresentation
bin101111010101001010000…
…001010101010110011011
3102111221100112222110220012
4233111022001111112123
5411242141204403101
610530105334552135
7453662530514012
oct57251201252633
912457315873805
103252532106651
111044433643153
1244644250864b
131a7935380049
14b35cdb15a79
15599149cbbbb
hex2f54a05559b

3252532106651 has 2 divisors, whose sum is σ = 3252532106652. Its totient is φ = 3252532106650.

The previous prime is 3252532106617. The next prime is 3252532106653. The reversal of 3252532106651 is 1566012352523.

3252532106651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3252532106651 - 226 = 3252464997787 is a prime.

Together with 3252532106653, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3252532106599 and 3252532106608.

It is not a weakly prime, because it can be changed into another prime (3252532106653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1626266053325 + 1626266053326.

It is an arithmetic number, because the mean of its divisors is an integer number (1626266053326).

Almost surely, 23252532106651 is an apocalyptic number.

3252532106651 is a deficient number, since it is larger than the sum of its proper divisors (1).

3252532106651 is an equidigital number, since it uses as much as digits as its factorization.

3252532106651 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 41.

The spelling of 3252532106651 in words is "three trillion, two hundred fifty-two billion, five hundred thirty-two million, one hundred six thousand, six hundred fifty-one".