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3253000556341 is a prime number
BaseRepresentation
bin101111010101100101111…
…100010100111100110101
3102111222120012110012001201
4233111211330110330311
5411244121120300331
610530224031252501
7454010246334364
oct57254574247465
912458505405051
103253000556341
111044654010358
1244655337a131
131a79ab439603
14b36360177db
1559940bb1a61
hex2f565f14f35

3253000556341 has 2 divisors, whose sum is σ = 3253000556342. Its totient is φ = 3253000556340.

The previous prime is 3253000556297. The next prime is 3253000556357. The reversal of 3253000556341 is 1436550003523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3074688603441 + 178311952900 = 1753479^2 + 422270^2 .

It is a cyclic number.

It is not a de Polignac number, because 3253000556341 - 29 = 3253000555829 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3253000556341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3253000556441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1626500278170 + 1626500278171.

It is an arithmetic number, because the mean of its divisors is an integer number (1626500278171).

Almost surely, 23253000556341 is an apocalyptic number.

It is an amenable number.

3253000556341 is a deficient number, since it is larger than the sum of its proper divisors (1).

3253000556341 is an equidigital number, since it uses as much as digits as its factorization.

3253000556341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162000, while the sum is 37.

Adding to 3253000556341 its reverse (1436550003523), we get a palindrome (4689550559864).

The spelling of 3253000556341 in words is "three trillion, two hundred fifty-three billion, five hundred fifty-six thousand, three hundred forty-one".