Base | Representation |
---|---|
bin | 1001011101111100010… |
… | …11011000001110011111 |
3 | 1011002200122011212122010 |
4 | 10232332023120032133 |
5 | 20312220134413210 |
6 | 405240302522303 |
7 | 32334364404333 |
oct | 4567613301637 |
9 | 1132618155563 |
10 | 325313201055 |
11 | 115a67903977 |
12 | 5306a896393 |
13 | 248a520579b |
14 | 11a60d377c3 |
15 | 86deaeb920 |
hex | 4bbe2d839f |
325313201055 has 32 divisors (see below), whose sum is σ = 521611521984. Its totient is φ = 173130587136.
The previous prime is 325313201047. The next prime is 325313201063. The reversal of 325313201055 is 550102313523.
It is an interprime number because it is at equal distance from previous prime (325313201047) and next prime (325313201063).
It is not a de Polignac number, because 325313201055 - 23 = 325313201047 is a prime.
It is a super-2 number, since 2×3253132010552 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16817169 + ... + 16836501.
It is an arithmetic number, because the mean of its divisors is an integer number (16300360062).
Almost surely, 2325313201055 is an apocalyptic number.
325313201055 is a deficient number, since it is larger than the sum of its proper divisors (196298320929).
325313201055 is a wasteful number, since it uses less digits than its factorization.
325313201055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21675.
The product of its (nonzero) digits is 13500, while the sum is 30.
Adding to 325313201055 its reverse (550102313523), we get a palindrome (875415514578).
The spelling of 325313201055 in words is "three hundred twenty-five billion, three hundred thirteen million, two hundred one thousand, fifty-five".
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