Base | Representation |
---|---|
bin | 1001011101111100010… |
… | …11011000001111001111 |
3 | 1011002200122011212200220 |
4 | 10232332023120033033 |
5 | 20312220134413403 |
6 | 405240302522423 |
7 | 32334364404432 |
oct | 4567613301717 |
9 | 1132618155626 |
10 | 325313201103 |
11 | 115a67903a10 |
12 | 5306a896413 |
13 | 248a5205807 |
14 | 11a60d37819 |
15 | 86deaeb953 |
hex | 4bbe2d83cf |
325313201103 has 32 divisors (see below), whose sum is σ = 474452708352. Its totient is φ = 196630848000.
The previous prime is 325313201093. The next prime is 325313201111. The reversal of 325313201103 is 301102313523.
It is not a de Polignac number, because 325313201103 - 218 = 325312938959 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (325313201153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40910778 + ... + 40918728.
It is an arithmetic number, because the mean of its divisors is an integer number (14826647136).
Almost surely, 2325313201103 is an apocalyptic number.
325313201103 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
325313201103 is a deficient number, since it is larger than the sum of its proper divisors (149139507249).
325313201103 is a wasteful number, since it uses less digits than its factorization.
325313201103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11135.
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 325313201103 its reverse (301102313523), we get a palindrome (626415514626).
The spelling of 325313201103 in words is "three hundred twenty-five billion, three hundred thirteen million, two hundred one thousand, one hundred three".
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