3253440131 has 2 divisors, whose sum is σ = 3253440132. Its totient is φ = 3253440130.

The previous prime is 3253440109. The next prime is 3253440133. The reversal of 3253440131 is 1310443523.

3253440131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3253440131 is a prime.

It is a super-2 number, since 2×3253440131² = 21169745372002594322, which contains 22 as substring.

Together with 3253440133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3253440131.

It is not a weakly prime, because it can be changed into another prime (3253440133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1626720065 + 1626720066.

It is an arithmetic number, because the mean of its divisors is an integer number (1626720066).

Almost surely, 2^3253440131 is an apocalyptic number.

3253440131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3253440131 is an equidigital number, since it uses as much as digits as its factorization.

3253440131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 26.

The square root of 3253440131 is about 57038.9352197251. The cubic root of 3253440131 is about 1481.7704845018.

Adding to 3253440131 its reverse (1310443523), we get a palindrome (4563883654).

The spelling of 3253440131 in words is "three billion, two hundred fifty-three million, four hundred forty thousand, one hundred thirty-one".