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3254012213 is a prime number
BaseRepresentation
bin1100000111110100…
…0100100100110101
322101202222221120212
43001331010210311
523131011342323
61254520435205
7143431435034
oct30175044465
98352887525
103254012213
11141a8945a1
12769918b05
133cb20021a
1422c24871b
15140a1bb78
hexc1f44935

3254012213 has 2 divisors, whose sum is σ = 3254012214. Its totient is φ = 3254012212.

The previous prime is 3254012197. The next prime is 3254012263. The reversal of 3254012213 is 3122104523.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3012582769 + 241429444 = 54887^2 + 15538^2 .

It is a cyclic number.

It is not a de Polignac number, because 3254012213 - 24 = 3254012197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3254012263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1627006106 + 1627006107.

It is an arithmetic number, because the mean of its divisors is an integer number (1627006107).

Almost surely, 23254012213 is an apocalyptic number.

It is an amenable number.

3254012213 is a deficient number, since it is larger than the sum of its proper divisors (1).

3254012213 is an equidigital number, since it uses as much as digits as its factorization.

3254012213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 3254012213 is about 57043.9498369459. The cubic root of 3254012213 is about 1481.8573304768.

Adding to 3254012213 its reverse (3122104523), we get a palindrome (6376116736).

The spelling of 3254012213 in words is "three billion, two hundred fifty-four million, twelve thousand, two hundred thirteen".