Base | Representation |
---|---|
bin | 1001011110001000101… |
… | …01111010000000000101 |
3 | 1011002221211210022102111 |
4 | 10233010111322000011 |
5 | 20312423123433013 |
6 | 405254435341021 |
7 | 32340061444336 |
oct | 4570425720005 |
9 | 1132854708374 |
10 | 325416624133 |
11 | 116010223197 |
12 | 53099451771 |
13 | 248c0777383 |
14 | 11a7097a28d |
15 | 86e8c2a73d |
hex | 4bc457a005 |
325416624133 has 2 divisors, whose sum is σ = 325416624134. Its totient is φ = 325416624132.
The previous prime is 325416624101. The next prime is 325416624139. The reversal of 325416624133 is 331426614523.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 215698011489 + 109718612644 = 464433^2 + 331238^2 .
It is an emirp because it is prime and its reverse (331426614523) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 325416624133 - 25 = 325416624101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (325416624139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162708312066 + 162708312067.
It is an arithmetic number, because the mean of its divisors is an integer number (162708312067).
Almost surely, 2325416624133 is an apocalyptic number.
It is an amenable number.
325416624133 is a deficient number, since it is larger than the sum of its proper divisors (1).
325416624133 is an equidigital number, since it uses as much as digits as its factorization.
325416624133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 311040, while the sum is 40.
The spelling of 325416624133 in words is "three hundred twenty-five billion, four hundred sixteen million, six hundred twenty-four thousand, one hundred thirty-three".
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