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3255240121409 is a prime number
BaseRepresentation
bin101111010111101011011…
…011100101110001000001
3102112012100021120212210002
4233113223123211301001
5411313212432341114
610531234153045345
7454116612330533
oct57275333456101
912465307525702
103255240121409
1110455a3203781
12446a793b6855
131a7c77411843
14b37a9633853
1559a225e67de
hex2f5eb6e5c41

3255240121409 has 2 divisors, whose sum is σ = 3255240121410. Its totient is φ = 3255240121408.

The previous prime is 3255240121339. The next prime is 3255240121421. The reversal of 3255240121409 is 9041210425523.

3255240121409 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2527209678400 + 728030443009 = 1589720^2 + 853247^2 .

It is an emirp because it is prime and its reverse (9041210425523) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3255240121409 is a prime.

It is not a weakly prime, because it can be changed into another prime (3255240121909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1627620060704 + 1627620060705.

It is an arithmetic number, because the mean of its divisors is an integer number (1627620060705).

Almost surely, 23255240121409 is an apocalyptic number.

It is an amenable number.

3255240121409 is a deficient number, since it is larger than the sum of its proper divisors (1).

3255240121409 is an equidigital number, since it uses as much as digits as its factorization.

3255240121409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 38.

The spelling of 3255240121409 in words is "three trillion, two hundred fifty-five billion, two hundred forty million, one hundred twenty-one thousand, four hundred nine".