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3257667242441 is a prime number
BaseRepresentation
bin101111011001111100000…
…110010100100111001001
3102112102121102122101220122
4233121330012110213021
5411333200303224231
610532315054433025
7454234013452253
oct57317406244711
912472542571818
103257667242441
11104662925a727
12447436202775
131a8273204c31
14b3959b12cd3
1559b1572877b
hex2f67c1949c9

3257667242441 has 2 divisors, whose sum is σ = 3257667242442. Its totient is φ = 3257667242440.

The previous prime is 3257667242341. The next prime is 3257667242471. The reversal of 3257667242441 is 1442427667523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2844737623225 + 412929619216 = 1686635^2 + 642596^2 .

It is a cyclic number.

It is not a de Polignac number, because 3257667242441 - 218 = 3257666980297 is a prime.

It is a super-2 number, since 2×32576672424412 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3257667242471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1628833621220 + 1628833621221.

It is an arithmetic number, because the mean of its divisors is an integer number (1628833621221).

Almost surely, 23257667242441 is an apocalyptic number.

It is an amenable number.

3257667242441 is a deficient number, since it is larger than the sum of its proper divisors (1).

3257667242441 is an equidigital number, since it uses as much as digits as its factorization.

3257667242441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13547520, while the sum is 53.

The spelling of 3257667242441 in words is "three trillion, two hundred fifty-seven billion, six hundred sixty-seven million, two hundred forty-two thousand, four hundred forty-one".