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32765248011373 is a prime number
BaseRepresentation
bin1110111001100110000001…
…11101111111110001101101
311022000022211110200102010221
413130303000331333301231
513243311211442330443
6153404051440531341
76621132250563223
oct734630075776155
9138008743612127
1032765248011373
11a492733350179
12381215b320b51
131538998c237b7
14813bbc9b4b13
153bc4751a7eed
hex1dccc0f7fc6d

32765248011373 has 2 divisors, whose sum is σ = 32765248011374. Its totient is φ = 32765248011372.

The previous prime is 32765248011311. The next prime is 32765248011439. The reversal of 32765248011373 is 37311084256723.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18119648131524 + 14645599879849 = 4256718^2 + 3826957^2 .

It is a cyclic number.

It is not a de Polignac number, because 32765248011373 - 225 = 32765214456941 is a prime.

It is a super-2 number, since 2×327652480113732 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 32765248011373.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32765248011473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16382624005686 + 16382624005687.

It is an arithmetic number, because the mean of its divisors is an integer number (16382624005687).

Almost surely, 232765248011373 is an apocalyptic number.

It is an amenable number.

32765248011373 is a deficient number, since it is larger than the sum of its proper divisors (1).

32765248011373 is an equidigital number, since it uses as much as digits as its factorization.

32765248011373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5080320, while the sum is 52.

The spelling of 32765248011373 in words is "thirty-two trillion, seven hundred sixty-five billion, two hundred forty-eight million, eleven thousand, three hundred seventy-three".