Base | Representation |
---|---|
bin | 1001100011000100001… |
… | …10011000010100000101 |
3 | 1011100210022002010101221 |
4 | 10301202012120110011 |
5 | 20333333204312432 |
6 | 410413224120341 |
7 | 32462500333312 |
oct | 4614206302405 |
9 | 1140708063357 |
10 | 328063354117 |
11 | 117149235644 |
12 | 536b79060b1 |
13 | 24c22bcc1a5 |
14 | 11c422a3d09 |
15 | 880128bb97 |
hex | 4c62198505 |
328063354117 has 2 divisors, whose sum is σ = 328063354118. Its totient is φ = 328063354116.
The previous prime is 328063354109. The next prime is 328063354127. The reversal of 328063354117 is 711453360823.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 251713927521 + 76349426596 = 501711^2 + 276314^2 .
It is a cyclic number.
It is not a de Polignac number, because 328063354117 - 23 = 328063354109 is a prime.
It is a super-2 number, since 2×3280633541172 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (328063354127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 164031677058 + 164031677059.
It is an arithmetic number, because the mean of its divisors is an integer number (164031677059).
Almost surely, 2328063354117 is an apocalyptic number.
It is an amenable number.
328063354117 is a deficient number, since it is larger than the sum of its proper divisors (1).
328063354117 is an equidigital number, since it uses as much as digits as its factorization.
328063354117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 328063354117 in words is "three hundred twenty-eight billion, sixty-three million, three hundred fifty-four thousand, one hundred seventeen".
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