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328803307874471 is a prime number
BaseRepresentation
bin100101011000010110111110…
…0010111011110100010100111
31121010012021210212021200002002
41022300231330113132202213
5321044103133303440341
63123150053202035515
7126154153326013163
oct11260557427364247
91533167725250062
10328803307874471
1195848777457541
1230a6434a648b9b
1311161032667931
145b2a244b23ca3
152802dde05829b
hex12b0b7c5de8a7

328803307874471 has 2 divisors, whose sum is σ = 328803307874472. Its totient is φ = 328803307874470.

The previous prime is 328803307874347. The next prime is 328803307874477. The reversal of 328803307874471 is 174478703308823.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 328803307874471 - 234 = 328786128005287 is a prime.

It is a super-3 number, since 3×3288033078744713 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 328803307874398 and 328803307874407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (328803307874477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 164401653937235 + 164401653937236.

It is an arithmetic number, because the mean of its divisors is an integer number (164401653937236).

Almost surely, 2328803307874471 is an apocalyptic number.

328803307874471 is a deficient number, since it is larger than the sum of its proper divisors (1).

328803307874471 is an equidigital number, since it uses as much as digits as its factorization.

328803307874471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151732224, while the sum is 65.

The spelling of 328803307874471 in words is "three hundred twenty-eight trillion, eight hundred three billion, three hundred seven million, eight hundred seventy-four thousand, four hundred seventy-one".