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3295246083713 is a prime number
BaseRepresentation
bin101111111100111011111…
…110001110011010000001
3102200000121100212100000122
4233330323332032122001
5412442130444134323
611001452023430025
7460034161363253
oct57747376163201
912600540770018
103295246083713
111060562564341
124527832b5315
131ab9817a0b9c
14b56c2913cd3
155aab48a9ec8
hex2ff3bf8e681

3295246083713 has 2 divisors, whose sum is σ = 3295246083714. Its totient is φ = 3295246083712.

The previous prime is 3295246083607. The next prime is 3295246083817. The reversal of 3295246083713 is 3173806425923.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2964980935744 + 330265147969 = 1721912^2 + 574687^2 .

It is a cyclic number.

It is not a de Polignac number, because 3295246083713 - 228 = 3294977648257 is a prime.

It is not a weakly prime, because it can be changed into another prime (3295246083313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1647623041856 + 1647623041857.

It is an arithmetic number, because the mean of its divisors is an integer number (1647623041857).

It is a 1-persistent number, because it is pandigital, but 2⋅3295246083713 = 6590492167426 is not.

Almost surely, 23295246083713 is an apocalyptic number.

It is an amenable number.

3295246083713 is a deficient number, since it is larger than the sum of its proper divisors (1).

3295246083713 is an equidigital number, since it uses as much as digits as its factorization.

3295246083713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6531840, while the sum is 53.

The spelling of 3295246083713 in words is "three trillion, two hundred ninety-five billion, two hundred forty-six million, eighty-three thousand, seven hundred thirteen".