Base | Representation |
---|---|
bin | 1100010010101001… |
… | …1010001000010101 |
3 | 22111221111111110012 |
4 | 3010222122020111 |
5 | 23224124421123 |
6 | 1303222410005 |
7 | 144522605606 |
oct | 30452321025 |
9 | 8457444405 |
10 | 3299451413 |
11 | 14434aa755 |
12 | 780b90905 |
13 | 40774c71b |
14 | 2342b5dad |
15 | 1449e5378 |
hex | c4a9a215 |
3299451413 has 2 divisors, whose sum is σ = 3299451414. Its totient is φ = 3299451412.
The previous prime is 3299451377. The next prime is 3299451433. The reversal of 3299451413 is 3141549923.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3265322449 + 34128964 = 57143^2 + 5842^2 .
It is an emirp because it is prime and its reverse (3141549923) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3299451413 - 212 = 3299447317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3299451433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1649725706 + 1649725707.
It is an arithmetic number, because the mean of its divisors is an integer number (1649725707).
Almost surely, 23299451413 is an apocalyptic number.
It is an amenable number.
3299451413 is a deficient number, since it is larger than the sum of its proper divisors (1).
3299451413 is an equidigital number, since it uses as much as digits as its factorization.
3299451413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 116640, while the sum is 41.
The square root of 3299451413 is about 57440.8514299710. The cubic root of 3299451413 is about 1488.7230494555.
The spelling of 3299451413 in words is "three billion, two hundred ninety-nine million, four hundred fifty-one thousand, four hundred thirteen".
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