Base | Representation |
---|---|
bin | 110000000001011111001… |
… | …100111100101011101110 |
3 | 102200111012212210100100021 |
4 | 300001133030330223232 |
5 | 413032132310110014 |
6 | 11004020524152354 |
7 | 460266231061063 |
oct | 60013714745356 |
9 | 12614185710307 |
10 | 3300132113134 |
11 | 106263a5a858a |
12 | 4537076986ba |
13 | 1ac27cb3705c |
14 | b5a277c8c6a |
15 | 5ac9d7ec624 |
hex | 3005f33caee |
3300132113134 has 8 divisors (see below), whose sum is σ = 4950509296320. Its totient is φ = 1649962347696.
The previous prime is 3300132113087. The next prime is 3300132113149. The reversal of 3300132113134 is 4313112310033.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-4 number, since 4×33001321131344 (a number of 51 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3300132113099 and 3300132113108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51814654 + ... + 51878305.
It is an arithmetic number, because the mean of its divisors is an integer number (618813662040).
Almost surely, 23300132113134 is an apocalyptic number.
3300132113134 is a deficient number, since it is larger than the sum of its proper divisors (1650377183186).
3300132113134 is a wasteful number, since it uses less digits than its factorization.
3300132113134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103708874.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 3300132113134 its reverse (4313112310033), we get a palindrome (7613244423167).
The spelling of 3300132113134 in words is "three trillion, three hundred billion, one hundred thirty-two million, one hundred thirteen thousand, one hundred thirty-four".
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