Base | Representation |
---|---|
bin | 100101100001001110100111… |
… | …1001001101100110001110111 |
3 | 1121021111211021220122211110022 |
4 | 1023002131033021230301313 |
5 | 321224041202410000434 |
6 | 3125522054422315355 |
7 | 126341216513064035 |
oct | 11302351711546167 |
9 | 1537454256584408 |
10 | 330022320000119 |
11 | 96178752a80a6a |
12 | 31020653288b5b |
13 | 1121bc81a77316 |
14 | 5b6d246261555 |
15 | 2824987dc622e |
hex | 12c274f26cc77 |
330022320000119 has 2 divisors, whose sum is σ = 330022320000120. Its totient is φ = 330022320000118.
The previous prime is 330022319999963. The next prime is 330022320000161. The reversal of 330022320000119 is 911000023220033.
It is a strong prime.
It is an emirp because it is prime and its reverse (911000023220033) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 330022320000119 - 212 = 330022319996023 is a prime.
It is a super-2 number, since 2×3300223200001192 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (330022320080119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165011160000059 + 165011160000060.
It is an arithmetic number, because the mean of its divisors is an integer number (165011160000060).
Almost surely, 2330022320000119 is an apocalyptic number.
330022320000119 is a deficient number, since it is larger than the sum of its proper divisors (1).
330022320000119 is an equidigital number, since it uses as much as digits as its factorization.
330022320000119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 26.
The spelling of 330022320000119 in words is "three hundred thirty trillion, twenty-two billion, three hundred twenty million, one hundred nineteen", and thus it is an aban number.
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