Base | Representation |
---|---|
bin | 110000000001101011101… |
… | …101101001100001111111 |
3 | 102200111202111202022111111 |
4 | 300001223231221201333 |
5 | 413033100023341111 |
6 | 11004053423102451 |
7 | 460304360144161 |
oct | 60015355514177 |
9 | 12614674668444 |
10 | 3300342012031 |
11 | 1062738031749 |
12 | 453765a41a27 |
13 | 1ac2b4478b9c |
14 | b5a47626931 |
15 | 5acb1e5ea21 |
hex | 3006bb6987f |
3300342012031 has 2 divisors, whose sum is σ = 3300342012032. Its totient is φ = 3300342012030.
The previous prime is 3300342011917. The next prime is 3300342012041. The reversal of 3300342012031 is 1302102430033.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3300342012031 - 213 = 3300342003839 is a prime.
It is a super-2 number, since 2×33003420120312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3300342011993 and 3300342012011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3300342012041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650171006015 + 1650171006016.
It is an arithmetic number, because the mean of its divisors is an integer number (1650171006016).
Almost surely, 23300342012031 is an apocalyptic number.
3300342012031 is a deficient number, since it is larger than the sum of its proper divisors (1).
3300342012031 is an equidigital number, since it uses as much as digits as its factorization.
3300342012031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 3300342012031 its reverse (1302102430033), we get a palindrome (4602444442064).
The spelling of 3300342012031 in words is "three trillion, three hundred billion, three hundred forty-two million, twelve thousand, thirty-one".
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