330041144040131 has 2 divisors, whose sum is σ = 330041144040132. Its totient is φ = 330041144040130.

The previous prime is 330041144040073. The next prime is 330041144040133. The reversal of 330041144040131 is 131040441140033.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 330041144040131 - 2¹⁰ = 330041144039107 is a prime.

It is a super-2 number, since 2×330041144040131² (a number of 30 digits) contains 22 as substring.

Together with 330041144040133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 330041144040094 and 330041144040103.

It is not a weakly prime, because it can be changed into another prime (330041144040133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165020572020065 + 165020572020066.

It is an arithmetic number, because the mean of its divisors is an integer number (165020572020066).

Almost surely, 2^{330041144040131} is an apocalyptic number.

330041144040131 is a deficient number, since it is larger than the sum of its proper divisors (1).

330041144040131 is an equidigital number, since it uses as much as digits as its factorization.

330041144040131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 330041144040131 its reverse (131040441140033), we get a palindrome (461081585180164).

The spelling of 330041144040131 in words is "three hundred thirty trillion, forty-one billion, one hundred forty-four million, forty thousand, one hundred thirty-one".