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3301112745471 = 34723412147131
BaseRepresentation
bin110000000010011001101…
…001110000110111111111
3102200120202020000122000110
4300002121221300313333
5413041134330323341
611004302114401103
7460332436235352
oct60023151606777
912616666018013
103301112745471
111062aa30a3132
1245393bb90193
131ac3a8052888
14b5abbb34299
155ad09955216
hex30099a70dff

3301112745471 has 8 divisors (see below), whose sum is σ = 4495132249344. Its totient is φ = 2153917535960.

The previous prime is 3301112745433. The next prime is 3301112745479. The reversal of 3301112745471 is 1745472111033.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-3301112745471 is a prime.

It is a super-3 number, since 3×33011127454713 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3301112745479) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11706073425 + ... + 11706073706.

It is an arithmetic number, because the mean of its divisors is an integer number (561891531168).

Almost surely, 23301112745471 is an apocalyptic number.

3301112745471 is a deficient number, since it is larger than the sum of its proper divisors (1194019503873).

3301112745471 is a wasteful number, since it uses less digits than its factorization.

3301112745471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23412147181.

The product of its (nonzero) digits is 70560, while the sum is 39.

The spelling of 3301112745471 in words is "three trillion, three hundred one billion, one hundred twelve million, seven hundred forty-five thousand, four hundred seventy-one".

Divisors: 1 3 47 141 23412147131 70236441393 1100370915157 3301112745471