Base | Representation |
---|---|
bin | 1001100110111000100… |
… | …01111011000000111101 |
3 | 1011120002011020002120211 |
4 | 10303130101323000331 |
5 | 20402032434401224 |
6 | 411352451312421 |
7 | 32564340622033 |
oct | 4633421730075 |
9 | 1146064202524 |
10 | 330113200189 |
11 | 118000328303 |
12 | 53b8a2ab711 |
13 | 2518b7a9866 |
14 | 11d98616553 |
15 | 88c11e8894 |
hex | 4cdc47b03d |
330113200189 has 2 divisors, whose sum is σ = 330113200190. Its totient is φ = 330113200188.
The previous prime is 330113200139. The next prime is 330113200223. The reversal of 330113200189 is 981002311033.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 165269080089 + 164844120100 = 406533^2 + 406010^2 .
It is an emirp because it is prime and its reverse (981002311033) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 330113200189 - 29 = 330113199677 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 330113200189.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (330113200139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165056600094 + 165056600095.
It is an arithmetic number, because the mean of its divisors is an integer number (165056600095).
Almost surely, 2330113200189 is an apocalyptic number.
It is an amenable number.
330113200189 is a deficient number, since it is larger than the sum of its proper divisors (1).
330113200189 is an equidigital number, since it uses as much as digits as its factorization.
330113200189 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 330113200189 in words is "three hundred thirty billion, one hundred thirteen million, two hundred thousand, one hundred eighty-nine".
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