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3301322199949 is a prime number
BaseRepresentation
bin110000000010100110001…
…000110001001110001101
3102200121021211011000112201
4300002212020301032031
5413042101440344244
611004335000001501
7460340561460664
oct60024610611615
912617254130481
103301322199949
1110630a0353404
1245399a160291
131ac40c56a337
14b5adb897ddb
155ad1d02aad4
hex300a623138d

3301322199949 has 2 divisors, whose sum is σ = 3301322199950. Its totient is φ = 3301322199948.

The previous prime is 3301322199911. The next prime is 3301322200003. The reversal of 3301322199949 is 9499912231033.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2614009904100 + 687312295849 = 1616790^2 + 829043^2 .

It is a cyclic number.

It is not a de Polignac number, because 3301322199949 - 233 = 3292732265357 is a prime.

It is a super-2 number, since 2×33013221999492 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3301322199949.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3301322179949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650661099974 + 1650661099975.

It is an arithmetic number, because the mean of its divisors is an integer number (1650661099975).

Almost surely, 23301322199949 is an apocalyptic number.

It is an amenable number.

3301322199949 is a deficient number, since it is larger than the sum of its proper divisors (1).

3301322199949 is an equidigital number, since it uses as much as digits as its factorization.

3301322199949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2834352, while the sum is 55.

The spelling of 3301322199949 in words is "three trillion, three hundred one billion, three hundred twenty-two million, one hundred ninety-nine thousand, nine hundred forty-nine".