Base | Representation |
---|---|
bin | 1001100110111010111… |
… | …10101101110001100001 |
3 | 1011120010120002211220221 |
4 | 10303131132231301201 |
5 | 20402103113043131 |
6 | 411354451003041 |
7 | 32565004004413 |
oct | 4633536556141 |
9 | 1146116084827 |
10 | 330133331041 |
11 | 118010727978 |
12 | 53b94b99481 |
13 | 25192a076c7 |
14 | 11d9b1769b3 |
15 | 88c2d73411 |
hex | 4cdd7adc61 |
330133331041 has 2 divisors, whose sum is σ = 330133331042. Its totient is φ = 330133331040.
The previous prime is 330133331023. The next prime is 330133331071. The reversal of 330133331041 is 140133331033.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 224222137441 + 105911193600 = 473521^2 + 325440^2 .
It is a cyclic number.
It is not a de Polignac number, because 330133331041 - 25 = 330133331009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 330133330997 and 330133331015.
It is not a weakly prime, because it can be changed into another prime (330133331071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165066665520 + 165066665521.
It is an arithmetic number, because the mean of its divisors is an integer number (165066665521).
Almost surely, 2330133331041 is an apocalyptic number.
It is an amenable number.
330133331041 is a deficient number, since it is larger than the sum of its proper divisors (1).
330133331041 is an equidigital number, since it uses as much as digits as its factorization.
330133331041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 330133331041 its reverse (140133331033), we get a palindrome (470266662074).
The spelling of 330133331041 in words is "three hundred thirty billion, one hundred thirty-three million, three hundred thirty-one thousand, forty-one".
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