Base | Representation |
---|---|
bin | 100101100010100001011001… |
… | …1101110110001111000101111 |
3 | 1121022010211011210011111110221 |
4 | 1023011002303232301320233 |
5 | 321234444301340213403 |
6 | 3130135455440312211 |
7 | 126360112216362562 |
oct | 11305026356617057 |
9 | 1538124153144427 |
10 | 330200101101103 |
11 | 96237092855502 |
12 | 3104aba9912667 |
13 | 11232974aa0c6c |
14 | 5b77aad4a04d9 |
15 | 28293e08ccdbd |
hex | 12c50b3bb1e2f |
330200101101103 has 2 divisors, whose sum is σ = 330200101101104. Its totient is φ = 330200101101102.
The previous prime is 330200101101007. The next prime is 330200101101121. The reversal of 330200101101103 is 301101101002033.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 330200101101103 - 245 = 295015729012271 is a prime.
It is a super-3 number, since 3×3302001011011033 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (330200101102103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165100050550551 + 165100050550552.
It is an arithmetic number, because the mean of its divisors is an integer number (165100050550552).
Almost surely, 2330200101101103 is an apocalyptic number.
330200101101103 is a deficient number, since it is larger than the sum of its proper divisors (1).
330200101101103 is an equidigital number, since it uses as much as digits as its factorization.
330200101101103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 330200101101103 its reverse (301101101002033), we get a palindrome (631301202103136).
The spelling of 330200101101103 in words is "three hundred thirty trillion, two hundred billion, one hundred one million, one hundred one thousand, one hundred three".
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