Base | Representation |
---|---|
bin | 100101100010101111111001… |
… | …0101011101000010011101001 |
3 | 1121022020210111122122112022121 |
4 | 1023011133302223220103221 |
5 | 321241002020313323423 |
6 | 3130202043513351241 |
7 | 126362263346633623 |
oct | 11305376253502351 |
9 | 1538223448575277 |
10 | 330231222011113 |
11 | 96249302795845 |
12 | 31055034108521 |
13 | 11235894458407 |
14 | 5b793c272bc13 |
15 | 282a112b1d45d |
hex | 12c57f2ae84e9 |
330231222011113 has 2 divisors, whose sum is σ = 330231222011114. Its totient is φ = 330231222011112.
The previous prime is 330231222011087. The next prime is 330231222011147. The reversal of 330231222011113 is 311110222132033.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 289140198999129 + 41091023011984 = 17004123^2 + 6410228^2 .
It is a cyclic number.
It is not a de Polignac number, because 330231222011113 - 29 = 330231222010601 is a prime.
It is not a weakly prime, because it can be changed into another prime (330231222011153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165115611005556 + 165115611005557.
It is an arithmetic number, because the mean of its divisors is an integer number (165115611005557).
Almost surely, 2330231222011113 is an apocalyptic number.
It is an amenable number.
330231222011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
330231222011113 is an equidigital number, since it uses as much as digits as its factorization.
330231222011113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 330231222011113 its reverse (311110222132033), we get a palindrome (641341444143146).
The spelling of 330231222011113 in words is "three hundred thirty trillion, two hundred thirty-one billion, two hundred twenty-two million, eleven thousand, one hundred thirteen".
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