Base | Representation |
---|---|
bin | 110000000100100101110… |
… | …100111011010100101101 |
3 | 102200210211010020020011211 |
4 | 300010211310323110231 |
5 | 413110443401411333 |
6 | 11005331324314421 |
7 | 460444633536346 |
oct | 60044564732455 |
9 | 12623733206154 |
10 | 3303464482093 |
11 | 1063a9a640716 |
12 | 4542976a2a11 |
13 | 1ac6913406c9 |
14 | b5c621cd0cd |
15 | 5ade6145ecd |
hex | 30125d3b52d |
3303464482093 has 2 divisors, whose sum is σ = 3303464482094. Its totient is φ = 3303464482092.
The previous prime is 3303464482069. The next prime is 3303464482127. The reversal of 3303464482093 is 3902844643033.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2986543898244 + 316920583849 = 1728162^2 + 562957^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3303464482093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3303464482033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1651732241046 + 1651732241047.
It is an arithmetic number, because the mean of its divisors is an integer number (1651732241047).
Almost surely, 23303464482093 is an apocalyptic number.
It is an amenable number.
3303464482093 is a deficient number, since it is larger than the sum of its proper divisors (1).
3303464482093 is an equidigital number, since it uses as much as digits as its factorization.
3303464482093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4478976, while the sum is 49.
The spelling of 3303464482093 in words is "three trillion, three hundred three billion, four hundred sixty-four million, four hundred eighty-two thousand, ninety-three".
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