Base | Representation |
---|---|
bin | 110000000101010100111… |
… | …110100101101101000011 |
3 | 102200212212020202100021211 |
4 | 300011110332211231003 |
5 | 413114103404403011 |
6 | 11005542023430551 |
7 | 460503350465563 |
oct | 60052476455503 |
9 | 12625766670254 |
10 | 3304255544131 |
11 | 10643661272a3 |
12 | 4544785b5457 |
13 | 1ac7891b4259 |
14 | b5cd92acda3 |
15 | 5ae40804b21 |
hex | 30154fa5b43 |
3304255544131 has 2 divisors, whose sum is σ = 3304255544132. Its totient is φ = 3304255544130.
The previous prime is 3304255544129. The next prime is 3304255544141. The reversal of 3304255544131 is 1314455524033.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3304255544131 - 21 = 3304255544129 is a prime.
It is a super-2 number, since 2×33042555441312 (a number of 26 digits) contains 22 as substring.
Together with 3304255544129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3304255544141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1652127772065 + 1652127772066.
It is an arithmetic number, because the mean of its divisors is an integer number (1652127772066).
Almost surely, 23304255544131 is an apocalyptic number.
3304255544131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3304255544131 is an equidigital number, since it uses as much as digits as its factorization.
3304255544131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 40.
The spelling of 3304255544131 in words is "three trillion, three hundred four billion, two hundred fifty-five million, five hundred forty-four thousand, one hundred thirty-one".
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