Base | Representation |
---|---|
bin | 100101100100001110000000… |
… | …0001001100010111101010001 |
3 | 1121022222010010121112012022021 |
4 | 1023020130000021202331101 |
5 | 321302304410210421431 |
6 | 3130434545003011441 |
7 | 126413006331364501 |
oct | 11310340011427521 |
9 | 1538863117465267 |
10 | 330433311420241 |
11 | 96316a86a10a47 |
12 | 31088233509b81 |
13 | 1124b95c5c7943 |
14 | 5b850b40dda01 |
15 | 28304de716b11 |
hex | 12c8700262f51 |
330433311420241 has 2 divisors, whose sum is σ = 330433311420242. Its totient is φ = 330433311420240.
The previous prime is 330433311420227. The next prime is 330433311420259. The reversal of 330433311420241 is 142024113334033.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 273965526025216 + 56467785395025 = 16551904^2 + 7514505^2 .
It is a cyclic number.
It is not a de Polignac number, because 330433311420241 - 25 = 330433311420209 is a prime.
It is a super-2 number, since 2×3304333114202412 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 330433311420197 and 330433311420206.
It is not a weakly prime, because it can be changed into another prime (330433311420041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165216655710120 + 165216655710121.
It is an arithmetic number, because the mean of its divisors is an integer number (165216655710121).
Almost surely, 2330433311420241 is an apocalyptic number.
It is an amenable number.
330433311420241 is a deficient number, since it is larger than the sum of its proper divisors (1).
330433311420241 is an equidigital number, since it uses as much as digits as its factorization.
330433311420241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 330433311420241 its reverse (142024113334033), we get a palindrome (472457424754274).
The spelling of 330433311420241 in words is "three hundred thirty trillion, four hundred thirty-three billion, three hundred eleven million, four hundred twenty thousand, two hundred forty-one".
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