Base | Representation |
---|---|
bin | 100101101000011011100010… |
… | …1000110110110110101000111 |
3 | 1121102000110012021100001110001 |
4 | 1023100313011012312311013 |
5 | 321341300331202210143 |
6 | 3132000513431142131 |
7 | 126502560304406425 |
oct | 11320670506666507 |
9 | 1542013167301401 |
10 | 331012141444423 |
11 | 9651a50841635a |
12 | 31160454514947 |
13 | 1129140736902a |
14 | 5ba5104946115 |
15 | 28405bac5e14d |
hex | 12d0dc51b6d47 |
331012141444423 has 2 divisors, whose sum is σ = 331012141444424. Its totient is φ = 331012141444422.
The previous prime is 331012141444343. The next prime is 331012141444429. The reversal of 331012141444423 is 324444141210133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331012141444423 - 29 = 331012141443911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331012141444429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165506070722211 + 165506070722212.
It is an arithmetic number, because the mean of its divisors is an integer number (165506070722212).
Almost surely, 2331012141444423 is an apocalyptic number.
331012141444423 is a deficient number, since it is larger than the sum of its proper divisors (1).
331012141444423 is an equidigital number, since it uses as much as digits as its factorization.
331012141444423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 37.
Adding to 331012141444423 its reverse (324444141210133), we get a palindrome (655456282654556).
The spelling of 331012141444423 in words is "three hundred thirty-one trillion, twelve billion, one hundred forty-one million, four hundred forty-four thousand, four hundred twenty-three".
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